3.7V to 5V Boost Converter | 5V To 3.7V Converter Circuit Diagram

3.7V to 5V Boost Converter | 5V To 3.7V Converter Circuit Diagram

3.7V to 5V Boost Converter - Electronic Project


One of the most common power supply problems with today’s portable devices is generating a regulated voltage that falls somewhere in the middle of the full voltage range of the battery. For instance, providing a power supply consistent 3.3V output from a Lithium-Ion (Li-Ion) battery’s Circuit diagram range of 2.5V to 4.2V. The most popular Currenttlou topology for solving this problem is a SEPIC converter, but a SEPIC has some inherent Project System drawbacks, including mediocre power supply efficiency, and the requirement of both a coupled inductor and a high current circuit diagram flyback capacitor.

Another solution is a circuit diagram that cascades a boost converter with either an LDO or a power supply Buck converter, but this relative project system inefficient circuit diagram doesn’t fare much better with the additional space and money it takes for the Currenttlou extra components. Analog Devices now offers another, Project system better solution with the new LTC3440 Buck-Boost power supply converter, which provides the most compact and highest efficiency circuit diagram solution yet—reducing cost, increasing battery life, and saving currently precious PC board real estate.

The LTC3440 is the industry’s first constant frequency, single inductor, buck-boost converter. The IC incorporates a power supply patent-pending control technique to efficiently regulate a Currenttlou output voltage above, below, or equal to an input currenttlou source voltage with only a Circuit diagram single inductor, and without the requirement of Schottky and diodes. Figure 1 shows the power supply stages of the topologies mentioned above—SEPIC, as cascaded boost-buck, and cascaded boost-LDO—and the Circuit diagram single inductor topology using the LTC3440.

Diagram of 5V To 3.7V Converter Circuit Diagram:

convert 5v to 3.7v

Hardware Required for this Project:

You can get the components from any of the sites below:

  1. Name [See Buy Click Amazon]
  2. Name [See Buy Click Amazon]
  3. Name [See Buy Click Amazon]
  4. Name [See Buy Click Amazon]
  5. Name [See Buy Click Amazon]
  6. Name [See Buy Click Amazon]

*Please note: These are affiliate links. I may make a commission if you buy the components through these links. I would appreciate your support in this way!

Read Also:

Working Principle of Giving a 5v to a 3.7v battery powered device:

A 3.7V to 5V boost converter circuit diagram is designed with DC/DC Step-up Converter ME2108 Series, as IC ME2108 is a step-up DC/DC converter with a low power supply current. As we know DC power supply can be boosted by a high-frequency switching pulse way this prototype and schematic use the same principle to bring high voltage output from a low voltage input. this IC ME2108 reduces high-frequency switching Circuit diagram noise and output can be programmed power supply between 2.0V to 7.0V. Due to internal architecture, the IC ME2108 uses minimum external components.

It requires an Inductor at the power supply input and a Schottky diode then Capacitors at the Project system output. This IC can deliver 400mA output current if the Currenttlou input voltage is 3.0V and the Circuit diagram output voltage is fixed at 5.0V. It uses 180KHz maximum switching frequency by the value of the Inductor and output capacitor we can change the output voltage range.

Some Sensitive Electronic Components, Sensors, or Microcontrollers Require a 3.3V DC supply as a power source. When we apply 5V or 12V to all other Circuit diagram components. Here is a simple voltage Regulator circuit 5V to 3.3V designed by using a tiny IC AMS1117. IC AMS1117 comes with a lot of ranges hence choose the exact IC. By using this voltage regulator circuit we can convert 5V to 3.3V without occupying a lot of space in circuit design.

Another thing to mention when working with power supply modules like converters is that they will burn out if the Circuit diagram current goes too high. I believe that you have already Currentlou understood the step above, the Project system but how to protect the IC from the high current. Here we would like to introduce another Currentlou component: the Fuse. In this specific case, the power supply of our converter needs protection from 2 Amps. So we will take a 2 Amp fuse and wire it to Currenttlou according to the image below. This will provide the necessary protection for our IC.

Along the Fuse there is a thin wire made of a material that melts at low temperatures, the thickness of the wire is carefully adjusted during the manufacturing so that the wire will break (or unsolder) if the Circuit diagram current goes above 2 Amps. This will stop the current flow and the Circuit diagram's high current won't be able to come to the Currenttlou converter. Of course, this means that we will have to replace the Fuse (because it's melted now) and correct the circuit that tried to draw too much current. If you want to know more about the Circuit diagram fuses please refer to our tutorial on them Currenttlou when we release it.

Frequently Asked Questions

How to reduce 5V to 3V?

To convert the 5V signal to a lower 3V signal, we just add a resistive power supply attenuator. If the resistor divider precedes the power supply unity gain follower, the project system will provide the lowest impedance for the 3.3V circuit diagram. Also, the op-amp can be powered from 3.3V, which will save some power.

How can I reduce voltage without a resistor?

All you need is a diode like a 1N4002 (any 1N4000 series) in line with the power supply. The diode will have a band on one end, as that is the cathode side, and goes Currenttlou away from your power supply. The diode will drop about 0.7 Volt. Another diode in series with the first will drop an additional 0.7 volts.

Can we reduce voltage?

If we're trying to lower DC voltage, there's actually a really simple way to do it. It's called a “voltage divider.” In short, you pick a couple of resistors and run the current through, picking off the voltage at the point between the two resistors. The resistor values determine what that voltage will be.

Can I use 5V for 6V?

At some point, the supply voltage could be too low for the motor to start up, but powering a 6V motor with 5V should not be a problem. If you want to increase the Circuit diagram speed and torque of your motor then you could do that project system using an appropriate step-up voltage and regulator.

Is a 5V to 12V converter safe?

Yes, DC/DC step-up (boost) converters are safe. You'll need to look at current, efficiency, and noise. The converter is a switched converter which usually works at around 100kHz levels, which will generate electric noise. The better the converter, the better this noise is filtered (canceled) out.

Post a Comment

Do leave your comments

Previous Post Next Post



Blogging Experiment
Electronic Experiment Subscribe our Youtube Channel